What is expand (s-1)/((s-3)(s^2+2s+2)) ?

The solution to expand (s-1)/((s-3)(s^2+2s+2)) is (s-1)/(s^3-s^2-4s-6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (s-1)/((s-3)(s^2+2s+2))

expand

\frac{s - 1}{( s - 3 ) ( s ^{2} + 2 s + 2 )}

\frac{s - 1}{s ^{3} - s ^{2} - 4 s - 6}

Solution steps

\frac{s - 1}{( s - 3 ) ( s ^{2} + 2 s + 2 )}

Expand

(s - 3) (s^{2} + 2 s + 2) : s^{3} - s^{2} - 4 s - 6

= \frac{s - 1}{s ^{3} - s ^{2} - 4 s - 6}

\frac{A x ^{4} + B x ^{3} + 541 x ^{2} - 228 x + 36}{( 3 x - 2 ) ^{2}}

2 (1 + lo g_{2} (3))

(A^{t})^{t}

(- 3 + i)^{20}

\frac{b}{x ^{2} ( x + a )}

What is expand (s-1)/((s-3)(s^2+2s+2)) ?
The solution to expand (s-1)/((s-3)(s^2+2s+2)) is (s-1)/(s^3-s^2-4s-6)