What is expand (x^2-9x)/((x+3)(x-3)) ?

The solution to expand (x^2-9x)/((x+3)(x-3)) is (x^2-9x)/(x^2-9)

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expand (x^2-9x)/((x+3)(x-3))

expand

\frac{x ^{2} - 9 x}{( x + 3 ) ( x - 3 )}

\frac{x ^{2} - 9 x}{x ^{2} - 9}

Solution steps

\frac{x ^{2} - 9 x}{( x + 3 ) ( x - 3 )}

Expand

(x + 3) (x - 3) : x^{2} - 9

= \frac{x ^{2} - 9 x}{x ^{2} - 9}

3 x^{2} tan (x) + sec^{2} (x) (x^{3} - 2)

x^{2} y d x - 2 x (x^{2} + y^{2}) d y

\frac{m}{( m x + n ) ( - m x + n )}

\frac{( 2 + y ) ^{2}}{4}

(3 - 3 i)^{7}

What is expand (x^2-9x)/((x+3)(x-3)) ?
The solution to expand (x^2-9x)/((x+3)(x-3)) is (x^2-9x)/(x^2-9)