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Popular >

expand (e^{-x})/(x(x-3)(x-2))+1/((x-3)(x-2))

Solution

expand

\frac{e ^{- x}}{x ( x - 3 ) ( x - 2 )} + \frac{1}{( x - 3 ) ( x - 2 )}

Solution

\frac{e ^{- x}}{x ^{3} - 5 x ^{2} + 6 x} + \frac{1}{x ^{2} - 5 x + 6}

Solution steps

\frac{e ^{- x}}{x ( x - 3 ) ( x - 2 )} + \frac{1}{( x - 3 ) ( x - 2 )}

Expand

x (x - 3) (x - 2) : x^{3} - 5 x^{2} + 6 x

= \frac{e ^{- x}}{x ^{3} - 5 x ^{2} + 6 x} + \frac{1}{( x - 3 ) ( x - 2 )}

Expand

(x - 3) (x - 2) : x^{2} - 5 x + 6

= \frac{e ^{- x}}{x ^{3} - 5 x ^{2} + 6 x} + \frac{1}{x ^{2} - 5 x + 6}

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Frequently Asked Questions (FAQ)

What is expand (e^{-x})/(x(x-3)(x-2))+1/((x-3)(x-2)) ?
The solution to expand (e^{-x})/(x(x-3)(x-2))+1/((x-3)(x-2)) is (e^{-x})/(x^3-5x^2+6x)+1/(x^2-5x+6)