What is expand (d^2)/(d^2x)(x^3+y^3=1) ?

The solution to expand (d^2)/(d^2x)(x^3+y^3=1) is x^2+(y^3)/x =1

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expand (d^2)/(d^2x)(x^3+y^3=1)

expand

\frac{d ^{2}}{d ^{2} x} (x^{3} + y^{3} = 1)

x^{2} + \frac{y ^{3}}{x} = 1

Solution steps

\frac{d ^{2}}{d ^{2} x} (x^{3} + y^{3} = 1)

= \frac{d ^{2}}{d ^{2} x} (x^{3} + 1 = y^{3})

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{d ^{2}}{d ^{2} x}, b = x^{3}, c = y^{3} = 1

\frac{d ^{2}}{d ^{2} x} x^{3} + \frac{d ^{2}}{d ^{2} x} y^{3} = 1

Expand

\frac{d ^{2}}{d ^{2} x} x^{3} + \frac{d ^{2}}{d ^{2} x} y^{3} : x^{2} + \frac{y ^{3}}{x}

x^{2} + \frac{y ^{3}}{x} = 1

(0, - 5) (x - 1)

\frac{s ^{2} + s - 10 + e ^{- s}}{( s - 1 ) ( s - 2 ) ( s + 4 )}

24 e^{- 20 t} + 20 (\frac{6}{5} - \frac{6}{5} e^{- 20 t})

\frac{\partial}{\partial u} ((x) (u^{4} + v w))

What is expand (d^2)/(d^2x)(x^3+y^3=1) ?
The solution to expand (d^2)/(d^2x)(x^3+y^3=1) is x^2+(y^3)/x =1