What is expand (derivative of (2x+3(2x-3)))/x ?

The solution to expand (derivative of (2x+3(2x-3)))/x is (derivative of 4x^2-9)/x

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expand (derivative of (2x+3(2x-3)))/x

expand

\frac{\frac{d}{d x} ( ( 2 x + 3 ) ( 2 x - 3 ) )}{x}

\frac{\frac{d}{d x} ( 4 x ^{2} - 9 )}{x}

Solution steps

\frac{\frac{d}{d x} ( ( 2 x + 3 ) ( 2 x - 3 ) )}{x}

Expand

(2 x + 3) (2 x - 3) : 4 x^{2} - 9

= \frac{\frac{d}{d x} ( 4 x ^{2} - 9 )}{x}

3 (1 + sin (a)) (1 - sin (a))

(x^{2} - 5 x + 4) d x

\frac{4 ( - n - 2 )}{n}

3.275 (1 - e^{- \frac{0.26}{( 52 , 68 \cdot 1 0 ^{- 3} )}})

(\frac{7}{3} x^{3} + 6) (\frac{7}{3} x^{3} - 6)

What is expand (derivative of (2x+3(2x-3)))/x ?
The solution to expand (derivative of (2x+3(2x-3)))/x is (derivative of 4x^2-9)/x