What is expand (2s+3)/(s(s+1)(2s^2+3s-5)) ?

The solution to expand (2s+3)/(s(s+1)(2s^2+3s-5)) is (2s+3)/(2s^4+5s^3-2s^2-5s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2s+3)/(s(s+1)(2s^2+3s-5))

expand

\frac{2 s + 3}{s ( s + 1 ) ( 2 s ^{2} + 3 s - 5 )}

\frac{2 s + 3}{2 s ^{4} + 5 s ^{3} - 2 s ^{2} - 5 s}

Solution steps

\frac{2 s + 3}{s ( s + 1 ) ( 2 s ^{2} + 3 s - 5 )}

Expand

s (s + 1) (2 s^{2} + 3 s - 5) : 2 s^{4} + 5 s^{3} - 2 s^{2} - 5 s

= \frac{2 s + 3}{2 s ^{4} + 5 s ^{3} - 2 s ^{2} - 5 s}

(2 - 4 x)^{2}

\frac{20160 e ^{- 0.84 x}}{( 1 + 3 e ^{- 0.84 x} ) ^{2}}

(sin (x) - csc (x)) 2

\frac{( 3 y ^{2} + x ) ^{7}}{2187}

(110 - 12 x) x

What is expand (2s+3)/(s(s+1)(2s^2+3s-5)) ?
The solution to expand (2s+3)/(s(s+1)(2s^2+3s-5)) is (2s+3)/(2s^4+5s^3-2s^2-5s)