What is the answer to 3x-2(2x+3)=5-[2x-3(4-x)] ?

The answer to 3x-2(2x+3)=5-[2x-3(4-x)] is x= 23/4

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3x-2(2x+3)=5-[2x-3(4-x)]

3 x - 2 (2 x + 3) = 5 - [2 x - 3 (4 - x)]

x = \frac{23}{4}

Decimal Notation

x = 5.75

Solution steps

3 x - 2 (2 x + 3) = 5 - [2 x - 3 (4 - x)]

Expand

- 2 (2 x + 3) : - 4 x - 6

3 x - 4 x - 6 = 5 - [2 x - 3 (4 - x)]

Add similar elements:

3 x - 4 x = - x

- x - 6 = 5 - [2 x - 3 (4 - x)]

Expand

5 - (2 x - 3 (4 - x)) : - 5 x + 17

- x - 6 = - 5 x + 17

Move

6

to the right side

- x = - 5 x + 23

Move

5 x

to the left side

4 x = 23

Divide both sides by

4

x = \frac{23}{4}

7 - (- 8) - x = 4 - (2 - 9)

9 v - 14 = 6 v - 2

y^{2} - 9 y + 18

x^{2} - 2 x - 48 < 0

- 2 + \frac{x}{x + 2} \leq \frac{1 - x}{x - 2}

What is the answer to 3x-2(2x+3)=5-[2x-3(4-x)] ?
The answer to 3x-2(2x+3)=5-[2x-3(4-x)] is x= 23/4
Solve for x: 3x-2(2x+3)=5-[2x-3(4-x)]
The solution is x= 23/4