What is expand (t^2-e^{5t}+13)*\H(t-θ) ?

The solution to expand (t^2-e^{5t}+13)*\H(t-θ) is t^2\H(t-θ)-e^{5t}\H(t-θ)+13\H(t-θ)

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expand (t^2-e^{5t}+13)*\H(t-θ)

expand

(t^{2} - e^{5 t} + 13) \cdot H (t - θ)

t^{2} H (t - θ) - e^{5 t} H (t - θ) + 13 H (t - θ)

Solution steps

(t^{2} - e^{5 t} + 13) H (t - θ)

= H (t - θ) (t^{2} - e^{5 t} + 13)

Distribute parentheses

= H (t - θ) t^{2} + H (t - θ) (- e^{5 t}) + H (t - θ) \cdot 13

Apply minus-plus rules

+ (- a) = - a

= t^{2} H (t - θ) - e^{5 t} H (t - θ) + 13 H (t - θ)

(a + bi + 1)^{2}

(x^{2} + 3 - 2) \times (x^{2} + 3 + 2)

\frac{( t - 3 ) ^{2}}{4}

A (- 1, 8) e B (- 5, - 1)

1400 (7 - x) + 2800 9 + x^{2}

What is expand (t^2-e^{5t}+13)*\H(t-θ) ?
The solution to expand (t^2-e^{5t}+13)*\H(t-θ) is t^2\H(t-θ)-e^{5t}\H(t-θ)+13\H(t-θ)