What is expand (2x^2-3)((1/x)+5) ?

The solution to expand (2x^2-3)((1/x)+5) is 2x+10x^2-3/x-15

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expand (2x^2-3)((1/x)+5)

expand

(2 x^{2} - 3) ((\frac{1}{x}) + 5)

2 x + 10 x^{2} - \frac{3}{x} - 15

Solution steps

(2 x^{2} - 3) ((\frac{1}{x}) + 5)

Simplify

(\frac{1}{x}) + 5 : \frac{1}{x} + 5

= (2 x^{2} - 3) (\frac{1}{x} + 5)

Apply FOIL method

(2 x^{2} - 3) (\frac{1}{x} + 5) : 2 x + 10 x^{2} - \frac{3}{x} - 15

= 2 x + 10 x^{2} - \frac{3}{x} - 15

\frac{3 x + 2}{x ( x ^{2} + 9 )}

\frac{π ( - ln ( 4 + 17 ) + 132 17 )}{256}

- \frac{( 19 + 265 ) k}{8} + 4 k

\frac{( x - 4 ) ^{2}}{4}

(\frac{2}{x ^{2}} + 3 y^{2}) (\frac{x ^{2}}{2} + \frac{1}{3 y ^{2}})

What is expand (2x^2-3)((1/x)+5) ?
The solution to expand (2x^2-3)((1/x)+5) is 2x+10x^2-3/x-15