What is expand ((x-1)^2)/(x^2-2x') ?

The solution to expand ((x-1)^2)/(x^2-2x') is (x^2-2x+1)/(x^2-2x')

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x-1)^2)/(x^2-2x')

expand

\frac{( x - 1 ) ^{2}}{x ^{2} - 2 x ^{'}}

\frac{x ^{2} - 2 x + 1}{x ^{2} - 2 x '}

Solution steps

\frac{( x - 1 ) ^{2}}{x ^{2} - 2 x ^{'}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{x ^{2} - 2 x + 1}{x ^{2} - 2 x ^{^{'}}}

- 3 (x - 3) (x - \frac{1}{2})

(5 x + 7 y + 2) (x - 7 y + 2)

(16 + 83) \cdot 4

\frac{( ( k + 1 ) ! - 1 )}{( k + 1 ) !} + \frac{( ( k + 1 ) )}{( k + 2 ) !}

\frac{4 ( 3 2 + 13 )}{3} - 42 - 2

What is expand ((x-1)^2)/(x^2-2x') ?
The solution to expand ((x-1)^2)/(x^2-2x') is (x^2-2x+1)/(x^2-2x')