What is expand (sin(2θ)+2sin(θ))(1-cos(θ)) ?

The solution to expand (sin(2θ)+2sin(θ))(1-cos(θ)) is 2sin(θ)-cos(θ)sin(2θ)

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expand (sin(2θ)+2sin(θ))(1-cos(θ))

expand

(sin (2 θ) + 2 sin (θ)) (1 - cos (θ))

2 sin (θ) - cos (θ) sin (2 θ)

Solution steps

(sin (2 θ) + 2 sin (θ)) (1 - cos (θ))

Apply FOIL method

(sin (2 θ) + 2 sin (θ)) (1 - cos (θ)) : 2 sin (θ) - cos (θ) sin (2 θ)

= 2 sin (θ) - cos (θ) sin (2 θ)

x (x - 10 x)

\frac{( sin ( x ) e ^{x} ) - ( e ^{x} \cdot cos ( x ) )}{( sin ( x ) ) ^{2}}

\frac{( x + 2 ) ( x - 1 )}{x - 2}

\frac{7 !}{2 ! 5 !}

(x + 1) (x - 5) (x - 2 + i) (x + \frac{14 - 5 i}{17})

What is expand (sin(2θ)+2sin(θ))(1-cos(θ)) ?
The solution to expand (sin(2θ)+2sin(θ))(1-cos(θ)) is 2sin(θ)-cos(θ)sin(2θ)