What is (x^2-(3y)/4+9/7)(x/2+(3y)/5-2) ?

The solution to (x^2-(3y)/4+9/7)(x/2+(3y)/5-2) is ((28x^2-21y+36)(-20+5x+6y))/(280)

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simplify (x^2-(3y)/4+9/7)(x/2+(3y)/5-2)

simplify

(x^{2} - \frac{3 y}{4} + \frac{9}{7}) (\frac{x}{2} + \frac{3 y}{5} - 2)

\frac{( 28 x ^{2} - 21 y + 36 ) ( - 20 + 5 x + 6 y )}{280}

Solution steps

(x^{2} - \frac{3 y}{4} + \frac{9}{7}) (\frac{x}{2} + \frac{3 y}{5} - 2)

Simplify

x^{2} - \frac{3 y}{4} + \frac{9}{7} : \frac{28 x ^{2} - 21 y + 36}{28}

= \frac{28 x ^{2} - 21 y + 36}{28} (\frac{x}{2} + \frac{3 y}{5} - 2)

Simplify

\frac{x}{2} + \frac{3 y}{5} - 2 : \frac{5 x + 6 y}{10} - 2

= \frac{28 x ^{2} - 21 y + 36}{28} (\frac{5 x + 6 y}{10} - 2)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 28 x ^{2} - 21 y + 36 ) ( \frac{5 x + 6 y}{10} - 2 )}{28}

Simplify

(28 x^{2} - 21 y + 36) (\frac{5 x + 6 y}{10} - 2) : \frac{( 28 x ^{2} - 21 y + 36 ) ( - 20 + 5 x + 6 y )}{10}

= \frac{\frac{( 28 x ^{2} - 21 y + 36 ) ( - 20 + 5 x + 6 y )}{10}}{28}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 28 x ^{2} - 21 y + 36 ) ( - 20 + 5 x + 6 y )}{10 \cdot 28}

Multiply the numbers:

10 \cdot 28 = 280

= \frac{( 28 x ^{2} - 21 y + 36 ) ( - 20 + 5 x + 6 y )}{280}

h (4 x + h + 4 x)

(1 + x - 5)^{2}

(3 x - 2)^{3} 4 x + 1

7 (5 + 6)

(P + \frac{a}{V ^{2}}) (V - b)

What is (x^2-(3y)/4+9/7)(x/2+(3y)/5-2) ?
The solution to (x^2-(3y)/4+9/7)(x/2+(3y)/5-2) is ((28x^2-21y+36)(-20+5x+6y))/(280)