What is expand (-1)^{x+1}((pi^3)/x-(6pi)/(x^3)) ?

The solution to expand (-1)^{x+1}((pi^3)/x-(6pi)/(x^3)) is (pi^3(-1)^{x+1})/x-(6pi(-1)^{x+1})/(x^3)

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expand (-1)^{x+1}((pi^3)/x-(6pi)/(x^3))

expand

(- 1)^{x + 1} (\frac{π ^{3}}{x} - \frac{6 π}{x ^{3}})

\frac{π ^{3} ( - 1 ) ^{x + 1}}{x} - \frac{6 π ( - 1 ) ^{x + 1}}{x ^{3}}

Solution steps

(- 1)^{x + 1} (\frac{π ^{3}}{x} - \frac{6 π}{x ^{3}})

Apply the distributive law:

a (b - c) = ab - a c

a = (- 1)^{x + 1}, b = \frac{π ^{3}}{x}, c = \frac{6 π}{x ^{3}}

= (- 1)^{x + 1} \frac{π ^{3}}{x} - (- 1)^{x + 1} \frac{6 π}{x ^{3}}

Simplify

(- 1)^{x + 1} \frac{π ^{3}}{x} - (- 1)^{x + 1} \frac{6 π}{x ^{3}} : \frac{π ^{3} ( - 1 ) ^{x + 1}}{x} - \frac{6 π ( - 1 ) ^{x + 1}}{x ^{3}}

= \frac{π ^{3} ( - 1 ) ^{x + 1}}{x} - \frac{6 π ( - 1 ) ^{x + 1}}{x ^{3}}

P (1, 4, 6) Q (- 2, 5, - 1) R (1, - 1, 1)

x (\frac{x}{2} - \frac{1}{4})

(y + \frac{1}{y ^{2}})^{6}

(x - 4) \times (x + 2)

\frac{\frac{d}{d x} ( ( x + 3 ) ( x - 1 ) )}{( x + 2 )}

What is expand (-1)^{x+1}((pi^3)/x-(6pi)/(x^3)) ?
The solution to expand (-1)^{x+1}((pi^3)/x-(6pi)/(x^3)) is (pi^3(-1)^{x+1})/x-(6pi(-1)^{x+1})/(x^3)