What are the solutions to the equation (200+5x)(100-2x)=15000 ?

The solutions to the equation (200+5x)(100-2x)=15000 are x=-5(sqrt(21)-1),x=5(1+sqrt(21))

Find the zeros of (200+5x)(100-2x)=15000

The zeros of (200+5x)(100-2x)=15000 are x=-5(sqrt(21)-1),x=5(1+sqrt(21))

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(200 + 5 x) (100 - 2 x) = 15000

x = - 5 (21 - 1), x = 5 (1 + 21)

Decimal Notation

x = - 17.91287 \dots, x = 27.91287 \dots

Solution steps

(200 + 5 x) (100 - 2 x) = 15000

Expand

(200 + 5 x) (100 - 2 x) : 20000 + 100 x - 10 x^{2}

20000 + 100 x - 10 x^{2} = 15000

Move

15000

to the left side

- 10 x^{2} + 100 x + 5000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 ( - 10 ) \cdot 5000}{2 ( - 10 )}

10 0^{2} - 4 (- 10) \cdot 5000 = 10021

x_{1, 2} = \frac{- 100 \pm 100 21}{2 ( - 10 )}

Separate the solutions

x_{1} = \frac{- 100 + 100 21}{2 ( - 10 )}, x_{2} = \frac{- 100 - 100 21}{2 ( - 10 )}

x = \frac{- 100 + 100 21}{2 ( - 10 )} : - 5 (21 - 1)

x = \frac{- 100 - 100 21}{2 ( - 10 )} : 5 (1 + 21)

The solutions to the quadratic equation are:

x = - 5 (21 - 1), x = 5 (1 + 21)

3 x^{2} + 2 x - 4 = 0

lo g_{2} (\frac{1}{8}) = - 3

(3 x^{4} y)^{3}

m^{2} - 16 m + 63

x^{2} + 14 x - 16 = 0

What are the solutions to the equation (200+5x)(100-2x)=15000 ?
The solutions to the equation (200+5x)(100-2x)=15000 are x=-5(sqrt(21)-1),x=5(1+sqrt(21))
Find the zeros of (200+5x)(100-2x)=15000
The zeros of (200+5x)(100-2x)=15000 are x=-5(sqrt(21)-1),x=5(1+sqrt(21))