What is expand (x^2+1)/(x(x+1)(x-1)) ?

The solution to expand (x^2+1)/(x(x+1)(x-1)) is (x^2+1)/(x^3-x)

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expand (x^2+1)/(x(x+1)(x-1))

expand

\frac{x ^{2} + 1}{x ( x + 1 ) ( x - 1 )}

\frac{x ^{2} + 1}{x ^{3} - x}

Solution steps

\frac{x ^{2} + 1}{x ( x + 1 ) ( x - 1 )}

Expand

x (x + 1) (x - 1) : x^{3} - x

= \frac{x ^{2} + 1}{x ^{3} - x}

- x (ln (x) + y^{2} \cdot ln (y)) d y

4 (x - \frac{3}{2})

4 (4 e^{2 x^{2}} x^{2} + e^{2 x^{2}})

(a, 2 b - 10, 5 c - 13) (15 - a, 2 d - 1, 11 - c)

(x - 3) (x - 4 i)^{2}

What is expand (x^2+1)/(x(x+1)(x-1)) ?
The solution to expand (x^2+1)/(x(x+1)(x-1)) is (x^2+1)/(x^3-x)