What is expand ((x-3)(x+2)(x-1))/(x(x-4)) ?

The solution to expand ((x-3)(x+2)(x-1))/(x(x-4)) is (x^3-2x^2-5x+6)/(x^2-4x)

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expand ((x-3)(x+2)(x-1))/(x(x-4))

expand

\frac{( x - 3 ) ( x + 2 ) ( x - 1 )}{x ( x - 4 )}

\frac{x ^{3} - 2 x ^{2} - 5 x + 6}{x ^{2} - 4 x}

Solution steps

\frac{( x - 3 ) ( x + 2 ) ( x - 1 )}{x ( x - 4 )}

Expand

x (x - 4) : x^{2} - 4 x

= \frac{( x - 3 ) ( x + 2 ) ( x - 1 )}{x ^{2} - 4 x}

Expand

(x - 3) (x + 2) (x - 1) : x^{3} - 2 x^{2} - 5 x + 6

= \frac{x ^{3} - 2 x ^{2} - 5 x + 6}{x ^{2} - 4 x}

\frac{3 ( 2 x ln ( x ) - x )}{ln ^{2} ( x )}

\frac{0 , 7}{1 - 0 , 7} (1 - 0. 7^{10})

\frac{d}{d x} ((P (x)) (x (36 - x)^{2}))

What is expand ((x-3)(x+2)(x-1))/(x(x-4)) ?
The solution to expand ((x-3)(x+2)(x-1))/(x(x-4)) is (x^3-2x^2-5x+6)/(x^2-4x)