What is expand ((x-3)(x+2))/((x+3)(x-4)) ?

The solution to expand ((x-3)(x+2))/((x+3)(x-4)) is (x^2-x-6)/(x^2-x-12)

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expand ((x-3)(x+2))/((x+3)(x-4))

expand

\frac{( x - 3 ) ( x + 2 )}{( x + 3 ) ( x - 4 )}

\frac{x ^{2} - x - 6}{x ^{2} - x - 12}

Solution steps

\frac{( x - 3 ) ( x + 2 )}{( x + 3 ) ( x - 4 )}

Expand

(x + 3) (x - 4) : x^{2} - x - 12

= \frac{( x - 3 ) ( x + 2 )}{x ^{2} - x - 12}

Expand

(x - 3) (x + 2) : x^{2} - x - 6

= \frac{x ^{2} - x - 6}{x ^{2} - x - 12}

\frac{1 - e ^{- s}}{s ^{2} ( s ^{2} + 4 )}

9 (x + 3 = 4 x - 3)

cosh (k (z + h))

\frac{a ^{2} - x ^{2}}{( x ^{2} + a ^{2} ) ^{2}}

tan (x) + sin (x) (csc (x) - sec (x) = 1)

What is expand ((x-3)(x+2))/((x+3)(x-4)) ?
The solution to expand ((x-3)(x+2))/((x+3)(x-4)) is (x^2-x-6)/(x^2-x-12)