What is expand ((x^2+3x+2)(4x^2-8x-5))/2 ?

The solution to expand ((x^2+3x+2)(4x^2-8x-5))/2 is 2x^4+2x^3-(21x^2)/2-(31x)/2-5

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expand ((x^2+3x+2)(4x^2-8x-5))/2

expand

\frac{( x ^{2} + 3 x + 2 ) ( 4 x ^{2} - 8 x - 5 )}{2}

2 x^{4} + 2 x^{3} - \frac{21 x ^{2}}{2} - \frac{31 x}{2} - 5

Solution steps

\frac{( x ^{2} + 3 x + 2 ) ( 4 x ^{2} - 8 x - 5 )}{2}

Expand

(x^{2} + 3 x + 2) (4 x^{2} - 8 x - 5) : 4 x^{4} + 4 x^{3} - 21 x^{2} - 31 x - 10

= \frac{4 x ^{4} + 4 x ^{3} - 21 x ^{2} - 31 x - 10}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{4} + 4 x ^{3} - 21 x ^{2} - 31 x - 10}{2} = \frac{4 x ^{4}}{2} + \frac{4 x ^{3}}{2} - \frac{21 x ^{2}}{2} - \frac{31 x}{2} - \frac{10}{2}

= \frac{4 x ^{4}}{2} + \frac{4 x ^{3}}{2} - \frac{21 x ^{2}}{2} - \frac{31 x}{2} - \frac{10}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 x^{4} + 2 x^{3} - \frac{21 x ^{2}}{2} - \frac{31 x}{2} - \frac{10}{2}

Divide the numbers:

\frac{10}{2} = 5

= 2 x^{4} + 2 x^{3} - \frac{21 x ^{2}}{2} - \frac{31 x}{2} - 5

\frac{( 2 x ^{4} - 6 x ^{2} )}{( x ^{2} - 1 ) ^{2}}

\frac{( e ^{x} - e ^{- x} ) ^{2}}{2}

(4 + t)^{3} (e^{t} + e^{t} t)

\frac{130}{( x ^{2} + 1 ) ( x ^{2} - 25 )}

(f (x) = 0.5 x^{2} - k (x) x - 8 k (x) (x)^{3} x - k (x)) k (x)

What is expand ((x^2+3x+2)(4x^2-8x-5))/2 ?
The solution to expand ((x^2+3x+2)(4x^2-8x-5))/2 is 2x^4+2x^3-(21x^2)/2-(31x)/2-5