What is expand (e^{2x})(e^x+e^xx) ?

The solution to expand (e^{2x})(e^x+e^xx) is e^{3x}+e^{3x}x

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expand (e^{2x})(e^x+e^xx)

expand

(e^{2 x}) (e^{x} + e^{x} x)

e^{3 x} + e^{3 x} x

Solution steps

(e^{2 x}) (e^{x} + e^{x} x)

Apply the distributive law:

a (b + c) = ab + a c

a = (e^{2 x}), b = e^{x}, c = e^{x} x

= (e^{2 x}) e^{x} + (e^{2 x}) e^{x} x

= e^{x} (e^{2 x}) + e^{x} x (e^{2 x})

Simplify

e^{x} (e^{2 x}) + e^{x} x (e^{2 x}) : e^{3 x} + e^{3 x} x

= e^{3 x} + e^{3 x} x

\frac{d}{d t} ((P (t, M)) (r (t, M) P (t, M) (M - P (t, M))))

(2 x - 1) \cdot lo g_{10} (5)

x (x + 1) - (4 - x) (x + 1 = 6 (4 - x))

15 n^{2} + n (lo g_{2} (n) + 1)

4 (1 - x)^{- 1} - 3 (3 + 2 x)^{- 1}

What is expand (e^{2x})(e^x+e^xx) ?
The solution to expand (e^{2x})(e^x+e^xx) is e^{3x}+e^{3x}x