What is expand e^{-3(t-3)}-e^{-3(t-5)} ?

The solution to expand e^{-3(t-3)}-e^{-3(t-5)} is e^{-3t+9}-e^{-3t+15}

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expand e^{-3(t-3)}-e^{-3(t-5)}

expand

e^{- 3 (t - 3)} - e^{- 3 (t - 5)}

e^{- 3 t + 9} - e^{- 3 t + 15}

Solution steps

e^{- 3 (t - 3)} - e^{- 3 (t - 5)}

Expand

- 3 (t - 3) : - 3 t + 9

= e^{- 3 t + 9} - e^{- 3 (t - 5)}

Expand

- 3 (t - 5) : - 3 t + 15

= e^{- 3 t + 9} - e^{- 3 t + 15}

1 + \frac{K \cdot 885.4}{( s + 40 ) ( s ^{2} + 98 )}

- 3 (ln (5 x) + 1)

\frac{4000 ( s ^{2} + 4 s + 4 )}{s ( s + 10 ) ( s + 100 )}

\frac{10 ( 12 - 15 )}{3}

a cos (b (x - c)) + d

What is expand e^{-3(t-3)}-e^{-3(t-5)} ?
The solution to expand e^{-3(t-3)}-e^{-3(t-5)} is e^{-3t+9}-e^{-3t+15}