What is expand (10x(-5x^3+y^3))/(y^5) ?

The solution to expand (10x(-5x^3+y^3))/(y^5) is -(50x^4)/(y^5)+(10x)/(y^2)

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expand (10x(-5x^3+y^3))/(y^5)

expand

\frac{10 x ( - 5 x ^{3} + y ^{3} )}{y ^{5}}

- \frac{50 x ^{4}}{y ^{5}} + \frac{10 x}{y ^{2}}

Solution steps

\frac{10 x ( - 5 x ^{3} + y ^{3} )}{y ^{5}}

Expand

10 x (- 5 x^{3} + y^{3}) : - 50 x^{4} + 10 x y^{3}

= \frac{- 50 x ^{4} + 10 x y ^{3}}{y ^{5}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 50 x ^{4} + 10 x y ^{3}}{y ^{5}} = - \frac{50 x ^{4}}{y ^{5}} + \frac{10 x y ^{3}}{y ^{5}}

= - \frac{50 x ^{4}}{y ^{5}} + \frac{10 x y ^{3}}{y ^{5}}

Cancel

\frac{10 x y ^{3}}{y ^{5}} : \frac{10 x}{y ^{2}}

= - \frac{50 x ^{4}}{y ^{5}} + \frac{10 x}{y ^{2}}

\frac{- s e ^{- π s} + s ( s ^{2} + 1 )}{( s ^{2} + 1 ) ( s ^{2} + 4 )}

\frac{d x}{x ( 4 - x )}

\frac{d ^{2}}{d x ^{2}} ((y) (x^{2} + y^{2} - 6 x - 8 y + 16))

(\frac{1}{x ^{2}} - 3 x)^{5}

\frac{x - 5}{( x - 1 ) ( x + 4 )}

What is expand (10x(-5x^3+y^3))/(y^5) ?
The solution to expand (10x(-5x^3+y^3))/(y^5) is -(50x^4)/(y^5)+(10x)/(y^2)