What is ((3a)/7-b)(5a^2+b^2) ?

The solution to ((3a)/7-b)(5a^2+b^2) is ((-7b+3a)(5a^2+b^2))/7

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simplify ((3a)/7-b)(5a^2+b^2)

simplify

(\frac{3 a}{7} - b) (5 a^{2} + b^{2})

\frac{( - 7 b + 3 a ) ( 5 a ^{2} + b ^{2} )}{7}

Solution steps

(\frac{3 a}{7} - b) (5 a^{2} + b^{2})

Simplify

\frac{3 a}{7} - b : \frac{- 7 b + 3 a}{7}

= \frac{- 7 b + 3 a}{7} (5 a^{2} + b^{2})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 7 b + 3 a ) ( 5 a ^{2} + b ^{2} )}{7}

t e^{t} u (t - 1)

x (ln (x y) + y^{2} = x)

(x^{2} + y) d x

(sin (3 x) - sin (x)) \cdot (cos (3 x) + cos (x))

\frac{( x ^{2} - 2 ) ( x + 3 )}{x + 4}

What is ((3a)/7-b)(5a^2+b^2) ?
The solution to ((3a)/7-b)(5a^2+b^2) is ((-7b+3a)(5a^2+b^2))/7