What is expand (2(2u^2v^2-1))/u ?

The solution to expand (2(2u^2v^2-1))/u is 4uv^2-2/u

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expand (2(2u^2v^2-1))/u

expand

\frac{2 ( 2 u ^{2} v ^{2} - 1 )}{u}

4 u v^{2} - \frac{2}{u}

Solution steps

\frac{2 ( 2 u ^{2} v ^{2} - 1 )}{u}

Expand

2 (2 u^{2} v^{2} - 1) : 4 u^{2} v^{2} - 2

= \frac{4 u ^{2} v ^{2} - 2}{u}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 u ^{2} v ^{2} - 2}{u} = \frac{4 u ^{2} v ^{2}}{u} - \frac{2}{u}

= \frac{4 u ^{2} v ^{2}}{u} - \frac{2}{u}

Cancel

\frac{4 u ^{2} v ^{2}}{u} : 4 u v^{2}

= 4 u v^{2} - \frac{2}{u}

\frac{2 x ^{3} - x ^{2} - x + 3}{x ( x - 1 ) ( 2 x + 3 )}

v (1, 2) f (2, - 2)

s (s + \frac{1}{15}) (3 s + 1)

\frac{15 s + 16}{( s + 1 ) ( 3 s + 2 )}

(3 x^{2} + 2) x^{\frac{1}{2}}

What is expand (2(2u^2v^2-1))/u ?
The solution to expand (2(2u^2v^2-1))/u is 4uv^2-2/u