What is expand (4x+y+6=18,0)(2y+2x+12=180) ?

The solution to expand (4x+y+6=18,0)(2y+2x+12=180) is 8xy+8x^2+48x=180

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expand (4x+y+6=18,0)(2y+2x+12=180)

expand

(4 x + y + 6 = 18, 0) (2 y + 2 x + 12 = 180)

8 x y + 8 x^{2} + 48 x = 180

Solution steps

(4 x + y + 6 = 18, 0) (2 y + 2 x + 12 = 180)

= (4 x + y + 6 \cdot 18 \cdot 0 =,) (2 y + 2 x + 12 \cdot 180 =)

Distribute parentheses

4 x \cdot 2 y + 4 x \cdot 2 x + 4 x \cdot 12 = 180 + y \cdot 2 y + y \cdot 2 x + y \cdot 12 = 180 + 6 = 18, 0 \cdot 2 y + 6 = 18, 0 \cdot 2 x + 6 = 18, 0 \cdot 12 = 180

4 \cdot 2 x y + 4 \cdot 2 xx + 4 \cdot 12 x = 180 + 2 yy + 2 x y + 12 y = 180 + 6 = 18, 0 \cdot 2 y + 6 = 18, 0 \cdot 2 x + 6 = 18, 0 \cdot 12 = 180

Expand

4 \cdot 2 x y + 4 \cdot 2 xx + 4 \cdot 12 x : 8 x y + 8 x^{2} + 48 x

8 x y + 8 x^{2} + 48 x = 180

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What is expand (4x+y+6=18,0)(2y+2x+12=180) ?
The solution to expand (4x+y+6=18,0)(2y+2x+12=180) is 8xy+8x^2+48x=180