What is expand (2x+1)/((x-3)(1-x)) ?

The solution to expand (2x+1)/((x-3)(1-x)) is (2x+1)/(4x-x^2-3)

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expand (2x+1)/((x-3)(1-x))

expand

\frac{2 x + 1}{( x - 3 ) ( 1 - x )}

\frac{2 x + 1}{4 x - x ^{2} - 3}

Solution steps

\frac{2 x + 1}{( x - 3 ) ( 1 - x )}

Expand

(x - 3) (1 - x) : 4 x - x^{2} - 3

= \frac{2 x + 1}{4 x - x ^{2} - 3}

x^{2} (\frac{4}{x} - \frac{x}{3})

0.03916 (1 - e^{(- 2.3 t)}) - 0.015 t

2 (7 i + 8 j) - 3 (8 + \frac{5 π}{6})

\frac{x ^{2}}{( x - 1 ) ^{3}}

(2 x y z^{3} w^{x^{2}} - \frac{4 t}{x})^{2}

What is expand (2x+1)/((x-3)(1-x)) ?
The solution to expand (2x+1)/((x-3)(1-x)) is (2x+1)/(4x-x^2-3)