What is 1/2 (log_{6}(x)+log_{8}(y)) ?

The solution to 1/2 (log_{6}(x)+log_{8}(y)) is 1/2 log_{6}(x)+1/2 log_{8}(y)

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simplify 1/2 (log_{6}(x)+log_{8}(y))

simplify

\frac{1}{2} (lo g_{6} (x) + lo g_{8} (y))

\frac{1}{2} lo g_{6} (x) + \frac{1}{2} lo g_{8} (y)

Solution steps

\frac{1}{2} (lo g_{6} (x) + lo g_{8} (y))

Apply the distributive law:

a (b + c) = ab + a c

\frac{1}{2} (lo g_{6} (x) + lo g_{8} (y)) = \frac{1}{2} lo g_{6} (x) + \frac{1}{2} lo g_{8} (y)

= \frac{1}{2} lo g_{6} (x) + \frac{1}{2} lo g_{8} (y)

(\frac{2 n ^{3}}{6} + \frac{3 n ^{2}}{6} + \frac{n}{6})^{2}

\frac{2 ( 7 - 4 )}{3}

(\frac{b}{a} (x - z) + y + c)^{3}

l {e^{4 t} (t - cos (t))}

(1 + x)^{2}

What is 1/2 (log_{6}(x)+log_{8}(y)) ?
The solution to 1/2 (log_{6}(x)+log_{8}(y)) is 1/2 log_{6}(x)+1/2 log_{8}(y)