What is expand (3(x^2+1)^{5/2}-5(x^2+1)^{3/2})/(15) ?

The solution to expand (3(x^2+1)^{5/2}-5(x^2+1)^{3/2})/(15) is ((x^2+1)^{5/2})/5-((x^2+1)^{3/2})/3

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expand (3(x^2+1)^{5/2}-5(x^2+1)^{3/2})/(15)

expand

\frac{3 ( x ^{2} + 1 ) ^{\frac{5}{2}} - 5 ( x ^{2} + 1 ) ^{\frac{3}{2}}}{15}

\frac{( x ^{2} + 1 ) ^{\frac{5}{2}}}{5} - \frac{( x ^{2} + 1 ) ^{\frac{3}{2}}}{3}

Solution steps

\frac{3 ( x ^{2} + 1 ) ^{\frac{5}{2}} - 5 ( x ^{2} + 1 ) ^{\frac{3}{2}}}{15}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 ( x ^{2} + 1 ) ^{\frac{5}{2}} - 5 ( x ^{2} + 1 ) ^{\frac{3}{2}}}{15} = \frac{3 ( x ^{2} + 1 ) ^{\frac{5}{2}}}{15} - \frac{5 ( x ^{2} + 1 ) ^{\frac{3}{2}}}{15}

= \frac{3 ( x ^{2} + 1 ) ^{\frac{5}{2}}}{15} - \frac{5 ( x ^{2} + 1 ) ^{\frac{3}{2}}}{15}

Cancel

\frac{3 ( x ^{2} + 1 ) ^{\frac{5}{2}}}{15} : \frac{( x ^{2} + 1 ) ^{\frac{5}{2}}}{5}

= \frac{( x ^{2} + 1 ) ^{\frac{5}{2}}}{5} - \frac{5 ( x ^{2} + 1 ) ^{\frac{3}{2}}}{15}

Cancel

\frac{5 ( x ^{2} + 1 ) ^{\frac{3}{2}}}{15} : \frac{( x ^{2} + 1 ) ^{\frac{3}{2}}}{3}

= \frac{( x ^{2} + 1 ) ^{\frac{5}{2}}}{5} - \frac{( x ^{2} + 1 ) ^{\frac{3}{2}}}{3}

(3 - e^{2 x^{2} + x})^{4}

\frac{2}{3} (a + 3) (b + (- \frac{4}{3}))

\frac{1}{81} (2 + s)^{4}

e^{(y + 1)^{2}} ((y^{2} + y) d x - x d y)

(63 - 5) (25 + 42)

What is expand (3(x^2+1)^{5/2}-5(x^2+1)^{3/2})/(15) ?
The solution to expand (3(x^2+1)^{5/2}-5(x^2+1)^{3/2})/(15) is ((x^2+1)^{5/2})/5-((x^2+1)^{3/2})/3