What is expand (1+2sin(θ))^2 ?

The solution to expand (1+2sin(θ))^2 is 1+4sin(θ)+4sin^2(θ)

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expand (1+2sin(θ))^2

expand

(1 + 2 sin (θ))^{2}

1 + 4 sin (θ) + 4 sin^{2} (θ)

Solution steps

(1 + 2 sin (θ))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(1 + 2 sin (θ))^{2} = 1^{2} + 2 \cdot 1 \cdot 2 sin (θ) + (2 sin (θ))^{2}

= 1^{2} + 2 \cdot 1 \cdot 2 sin (θ) + (2 sin (θ))^{2}

Simplify

1^{2} + 2 \cdot 1 \cdot 2 sin (θ) + (2 sin (θ))^{2} : 1 + 4 sin (θ) + 4 sin^{2} (θ)

= 1 + 4 sin (θ) + 4 sin^{2} (θ)

\frac{x ^{2} y ^{4} ( 6 x - 1 ) ^{2}}{4}

\frac{d}{d θ} ((x (θ)) (a (θ - sin (θ))))

\frac{k ( s + 4 )}{s ( s + 1 ) ( s + 3 )}

(2 - x - 4)^{2}

What is expand (1+2sin(θ))^2 ?
The solution to expand (1+2sin(θ))^2 is 1+4sin(θ)+4sin^2(θ)