What is expand x^{1/2}(x^{3/2}-4)(x^{1/2}+4) ?

The solution to expand x^{1/2}(x^{3/2}-4)(x^{1/2}+4) is x^{5/2}+4x^2-4x-16x^{1/2}

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expand x^{1/2}(x^{3/2}-4)(x^{1/2}+4)

expand

x^{\frac{1}{2}} (x^{\frac{3}{2}} - 4) (x^{\frac{1}{2}} + 4)

x^{\frac{5}{2}} + 4 x^{2} - 4 x - 16 x^{\frac{1}{2}}

Solution steps

x^{\frac{1}{2}} (x^{\frac{3}{2}} - 4) (x^{\frac{1}{2}} + 4)

Expand

x^{\frac{1}{2}} (x^{\frac{3}{2}} - 4) (x^{\frac{1}{2}} + 4) : x^{\frac{1}{2}} (x^{2} + x^{\frac{3}{2}} \cdot 4 - 4 x^{\frac{1}{2}} - 16)

= x^{\frac{1}{2}} (x^{2} + x^{\frac{3}{2}} \cdot 4 - 4 x^{\frac{1}{2}} - 16)

Distribute parentheses

= x^{\frac{1}{2}} x^{2} + x^{\frac{1}{2}} x^{\frac{3}{2}} \cdot 4 + x^{\frac{1}{2}} (- 4 x^{\frac{1}{2}}) + x^{\frac{1}{2}} (- 16)

x^{\frac{1}{2}} x^{2} = x^{\frac{5}{2}}

x^{\frac{1}{2}} x^{\frac{3}{2}} \cdot 4 = 4 x^{2}

x^{\frac{1}{2}} (- 4 x^{\frac{1}{2}}) = - 4 x

x^{\frac{1}{2}} (- 16) = - 16 x^{\frac{1}{2}}

= x^{\frac{5}{2}} + 4 x^{2} - 4 x - 16 x^{\frac{1}{2}}

(1 - ln (x)) d y

x + 4 (x - 4 + 3 x - 4)

(- \frac{1}{23 , 2 + 0 , 9 K}) \cdot (- 0.9 K^{2} + 53.6 K - 793.6)

\frac{1}{( z + 1 ) ( z + 2 )}

4 (4 cos (4 x) - sin (x) + (- 4) sin (4 x) cos (x))

What is expand x^{1/2}(x^{3/2}-4)(x^{1/2}+4) ?
The solution to expand x^{1/2}(x^{3/2}-4)(x^{1/2}+4) is x^{5/2}+4x^2-4x-16x^{1/2}