What are the solutions to the equation (5x+2)^2=12 ?

The solutions to the equation (5x+2)^2=12 are x=(2sqrt(3)-2)/5 ,x=(-2sqrt(3)-2)/5

Find the zeros of (5x+2)^2=12

The zeros of (5x+2)^2=12 are x=(2sqrt(3)-2)/5 ,x=(-2sqrt(3)-2)/5

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(5 x + 2)^{2} = 12

x = \frac{2 3 - 2}{5}, x = \frac{- 2 3 - 2}{5}

Decimal Notation

x = 0.29282 \dots, x = - 1.09282 \dots

Solution steps

(5 x + 2)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 2 = 12 : x = \frac{2 3 - 2}{5}

Solve

5 x + 2 = - 12 : x = \frac{- 2 3 - 2}{5}

The solutions to the quadratic equation are:

x = \frac{2 3 - 2}{5}, x = \frac{- 2 3 - 2}{5}

1^{- \frac{7}{4}}

3 x - 1 = 8

n^{2} = 9 n - 20

20 x + 12 \geq 14 x + 30

\frac{1}{2} (- 2)^{- 4} 4^{2}

What are the solutions to the equation (5x+2)^2=12 ?
The solutions to the equation (5x+2)^2=12 are x=(2sqrt(3)-2)/5 ,x=(-2sqrt(3)-2)/5
Find the zeros of (5x+2)^2=12
The zeros of (5x+2)^2=12 are x=(2sqrt(3)-2)/5 ,x=(-2sqrt(3)-2)/5