What is expand sin(x)ln(x)(2x-1) ?

The solution to expand sin(x)ln(x)(2x-1) is 2xsin(x)ln(x)-sin(x)ln(x)

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expand sin(x)ln(x)(2x-1)

expand

sin (x) ln (x) (2 x - 1)

2 x sin (x) ln (x) - sin (x) ln (x)

Solution steps

sin (x) ln (x) (2 x - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (x) ln (x), b = 2 x, c = 1

= sin (x) ln (x) \cdot 2 x - sin (x) ln (x) \cdot 1

= 2 x sin (x) ln (x) - 1 \cdot sin (x) ln (x)

Multiply:

1 \cdot sin (x) = sin (x)

= 2 x sin (x) ln (x) - sin (x) ln (x)

\frac{3}{( x - 3 ) ( x + 3 )}

\frac{( 2 x + 3 )}{( x ^{2} + x + 1 ) ^{2} ( x - 1 ) ^{3} ( x + 1 ) ^{2}}

lo g_{10} (4) x^{4}

(X - 1) (X - 2) (X - 3) (X - 4) (X - 5) (X - 6) (X - 7) (X - 8) (X - 9) (X - 10) (X - 11)

x (14 - \frac{x}{4000})

What is expand sin(x)ln(x)(2x-1) ?
The solution to expand sin(x)ln(x)(2x-1) is 2xsin(x)ln(x)-sin(x)ln(x)