What is expand-(x^3+6x^2+16x-32)/(2(x^2+4)(x^2+16)) ?

The solution to expand-(x^3+6x^2+16x-32)/(2(x^2+4)(x^2+16)) is -(x^3+6x^2+16x-32)/(2x^4+40x^2+128)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(x^3+6x^2+16x-32)/(2(x^2+4)(x^2+16))

expand

- \frac{x ^{3} + 6 x ^{2} + 16 x - 32}{2 ( x ^{2} + 4 ) ( x ^{2} + 16 )}

- \frac{x ^{3} + 6 x ^{2} + 16 x - 32}{2 x ^{4} + 40 x ^{2} + 128}

Solution steps

- \frac{x ^{3} + 6 x ^{2} + 16 x - 32}{2 ( x ^{2} + 4 ) ( x ^{2} + 16 )}

Expand

2 (x^{2} + 4) (x^{2} + 16) : 2 x^{4} + 40 x^{2} + 128

= - \frac{x ^{3} + 6 x ^{2} + 16 x - 32}{2 x ^{4} + 40 x ^{2} + 128}

\frac{s ^{2} + 6 s + 9}{( s + 4 ) ( s ^{2} - 3 s + 2 )}

\frac{1}{( s - 5 ) ^{2}}

\frac{2 e ^{x} ( - e ^{x} + 2 )}{( e ^{x} + 2 ) ^{3}}

8 x 2 - 24 x y + 6 y 2

(x - \frac{1}{3}) (x - \frac{2}{3})

What is expand-(x^3+6x^2+16x-32)/(2(x^2+4)(x^2+16)) ?
The solution to expand-(x^3+6x^2+16x-32)/(2(x^2+4)(x^2+16)) is -(x^3+6x^2+16x-32)/(2x^4+40x^2+128)