What is expand (sin(θ)-1)*(3sin(θ)) ?

The solution to expand (sin(θ)-1)*(3sin(θ)) is 3sin^2(θ)-3sin(θ)

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expand (sin(θ)-1)*(3sin(θ))

expand

(sin (θ) - 1) \cdot (3 sin (θ))

3 sin^{2} (θ) - 3 sin (θ)

Solution steps

(sin (θ) - 1) (3 sin (θ))

= (3 sin (θ)) (sin (θ) - 1)

Apply the distributive law:

a (b - c) = ab - a c

(3 sin (θ)) (sin (θ) - 1) = 3 sin (θ) sin (θ) - 3 sin (θ) \cdot 1

= 3 sin (θ) sin (θ) - 3 sin (θ) \cdot 1

Simplify

3 sin (θ) sin (θ) - 3 sin (θ) \cdot 1 : 3 sin^{2} (θ) - 3 sin (θ)

= 3 sin^{2} (θ) - 3 sin (θ)

(1 - x) (1 + 2 x)^{\frac{1}{2}}

\frac{1}{s ( s ^{2} + a ^{2} ) ^{2}}

(e^{- x} + e^{x})^{3}

11 (7 + 2)

\frac{3 C - ( - x ^{2} + 9 ) ^{\frac{3}{2}}}{3}

What is expand (sin(θ)-1)*(3sin(θ)) ?
The solution to expand (sin(θ)-1)*(3sin(θ)) is 3sin^2(θ)-3sin(θ)