What is expand 1/((x-1)(x^2+3)) ?

The solution to expand 1/((x-1)(x^2+3)) is 1/(x^3+3x-x^2-3)

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expand 1/((x-1)(x^2+3))

expand

\frac{1}{( x - 1 ) ( x ^{2} + 3 )}

\frac{1}{x ^{3} + 3 x - x ^{2} - 3}

Solution steps

\frac{1}{( x - 1 ) ( x ^{2} + 3 )}

Expand

(x - 1) (x^{2} + 3) : x^{3} + 3 x - x^{2} - 3

= \frac{1}{x ^{3} + 3 x - x ^{2} - 3}

(x - \frac{1}{2 x})^{10}

A \cdot (\frac{1}{B} + \frac{1}{C})

\frac{( 9 y ^{2} + 6 ) \cdot ln ( x )}{2} - \frac{( 3 y ^{2} + 2 ) ^{3}}{x}

2 (2 cos (u) + 2) (2 sin (u) + 4)^{2}

(3 x^{2} + 2 x y + y^{3}) d x + (x^{2} + y^{2}) d y

What is expand 1/((x-1)(x^2+3)) ?
The solution to expand 1/((x-1)(x^2+3)) is 1/(x^3+3x-x^2-3)