What is expand (x(x-4)(x-9))/(24) ?

The solution to expand (x(x-4)(x-9))/(24) is (x^3}{24}-(13x^2)/(24)+\frac{3x)/2

Popular >

expand (x(x-4)(x-9))/(24)

expand

\frac{x ( x - 4 ) ( x - 9 )}{24}

\frac{x ^{3}}{24} - \frac{13 x ^{2}}{24} + \frac{3 x}{2}

Solution steps

\frac{x ( x - 4 ) ( x - 9 )}{24}

Expand

x (x - 4) (x - 9) : x^{3} - 13 x^{2} + 36 x

= \frac{x ^{3} - 13 x ^{2} + 36 x}{24}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - 13 x ^{2} + 36 x}{24} = \frac{x ^{3}}{24} - \frac{13 x ^{2}}{24} + \frac{36 x}{24}

= \frac{x ^{3}}{24} - \frac{13 x ^{2}}{24} + \frac{36 x}{24}

Cancel

\frac{36 x}{24} : \frac{3 x}{2}

= \frac{x ^{3}}{24} - \frac{13 x ^{2}}{24} + \frac{3 x}{2}

2 (\frac{2 π ^{4}}{5} - \frac{x ^{4}}{36})

9 \cdot (x + \frac{1}{3})

\frac{( x ^{2} - 1 ) ln ( z )}{2}

(4 + 4 sin (x))^{2}

(x - 2 i)^{3}

What is expand (x(x-4)(x-9))/(24) ?
The solution to expand (x(x-4)(x-9))/(24) is (x^3}{24}-(13x^2)/(24)+\frac{3x)/2