What is expand (x(2x+1)(x-5))/((x+3)(3x-4)) ?

The solution to expand (x(2x+1)(x-5))/((x+3)(3x-4)) is (2x^3-9x^2-5x)/(3x^2+5x-12)

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expand (x(2x+1)(x-5))/((x+3)(3x-4))

expand

\frac{x ( 2 x + 1 ) ( x - 5 )}{( x + 3 ) ( 3 x - 4 )}

\frac{2 x ^{3} - 9 x ^{2} - 5 x}{3 x ^{2} + 5 x - 12}

Solution steps

\frac{x ( 2 x + 1 ) ( x - 5 )}{( x + 3 ) ( 3 x - 4 )}

Expand

(x + 3) (3 x - 4) : 3 x^{2} + 5 x - 12

= \frac{x ( 2 x + 1 ) ( x - 5 )}{3 x ^{2} + 5 x - 12}

Expand

x (2 x + 1) (x - 5) : 2 x^{3} - 9 x^{2} - 5 x

= \frac{2 x ^{3} - 9 x ^{2} - 5 x}{3 x ^{2} + 5 x - 12}

e^{x} (x^{2} + 2 x - 2)

(3 (1 - t) - i t)^{2}

(a + b)^{2} - 2 a b

\frac{( x - 4 ) ( x + 6 )}{x}

2 (3 + 7)

What is expand (x(2x+1)(x-5))/((x+3)(3x-4)) ?
The solution to expand (x(2x+1)(x-5))/((x+3)(3x-4)) is (2x^3-9x^2-5x)/(3x^2+5x-12)