What is expand (e^{x/(20)}-e^{-x/(20)})^2 ?

The solution to expand (e^{x/(20)}-e^{-x/(20)})^2 is e^{x/(10)}-2+e^{-x/(10)}

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expand (e^{x/(20)}-e^{-x/(20)})^2

expand

(e^{\frac{x}{20}} - e^{- \frac{x}{20}})^{2}

e^{\frac{x}{10}} - 2 + e^{- \frac{x}{10}}

Solution steps

(e^{\frac{x}{20}} - e^{- \frac{x}{20}})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = e^{\frac{x}{20}}, b = e^{- \frac{x}{20}}

= (e^{\frac{x}{20}})^{2} - 2 e^{\frac{x}{20}} e^{- \frac{x}{20}} + (e^{- \frac{x}{20}})^{2}

Simplify

(e^{\frac{x}{20}})^{2} - 2 e^{\frac{x}{20}} e^{- \frac{x}{20}} + (e^{- \frac{x}{20}})^{2} : e^{\frac{x}{10}} - 2 + e^{- \frac{x}{10}}

= e^{\frac{x}{10}} - 2 + e^{- \frac{x}{10}}

(2 + x) (2 x + \frac{1}{x})^{5}

\frac{( s ^{2} + 3 )}{( ( s ^{2} + 2 \cdot s + 5 ) \cdot ( s + 2 ) )}

u (t - \frac{7 π}{2}) \cdot sin (t)

y^{''} (x) - (1 + x) y

(A + B) \cdot B^{^{'}}

What is expand (e^{x/(20)}-e^{-x/(20)})^2 ?
The solution to expand (e^{x/(20)}-e^{-x/(20)})^2 is e^{x/(10)}-2+e^{-x/(10)}