What is expand (2t^2+t+1)/((x-3)(2x^2+1)) ?

The solution to expand (2t^2+t+1)/((x-3)(2x^2+1)) is (2t^2+t+1)/(2x^3+x-6x^2-3)

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expand (2t^2+t+1)/((x-3)(2x^2+1))

expand

\frac{2 t ^{2} + t + 1}{( x - 3 ) ( 2 x ^{2} + 1 )}

\frac{2 t ^{2} + t + 1}{2 x ^{3} + x - 6 x ^{2} - 3}

Solution steps

\frac{2 t ^{2} + t + 1}{( x - 3 ) ( 2 x ^{2} + 1 )}

Expand

(x - 3) (2 x^{2} + 1) : 2 x^{3} + x - 6 x^{2} - 3

= \frac{2 t ^{2} + t + 1}{2 x ^{3} + x - 6 x ^{2} - 3}

5 (14 ln (2) - 3)

u (t - 2 π) sin (t)

(1 - x^{2} - y^{2}) \cdot (1 + 4 x^{2} + 4 y^{2})

p^{\frac{3}{5}} (p^{\frac{2}{5}} - 3 p^{\frac{12}{5}})

(1 + x - 1) \cdot (1 - x - 1)

What is expand (2t^2+t+1)/((x-3)(2x^2+1)) ?
The solution to expand (2t^2+t+1)/((x-3)(2x^2+1)) is (2t^2+t+1)/(2x^3+x-6x^2-3)