What is expand (x^4-4x)^{1/2}*2(x^3-1) ?

The solution to expand (x^4-4x)^{1/2}*2(x^3-1) is 2(x^4-4x)^{1/2}x^3-2(x^4-4x)^{1/2}

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expand (x^4-4x)^{1/2}*2(x^3-1)

expand

(x^{4} - 4 x)^{\frac{1}{2}} \cdot 2 (x^{3} - 1)

2 (x^{4} - 4 x)^{\frac{1}{2}} x^{3} - 2 (x^{4} - 4 x)^{\frac{1}{2}}

Solution steps

(x^{4} - 4 x)^{\frac{1}{2}} \cdot 2 (x^{3} - 1)

= 2 (x^{4} - 4 x)^{\frac{1}{2}} (x^{3} - 1)

Apply the distributive law:

a (b - c) = ab - a c

2 (x^{4} - 4 x)^{\frac{1}{2}} (x^{3} - 1) = 2 (x^{4} - 4 x)^{\frac{1}{2}} x^{3} - 2 (x^{4} - 4 x)^{\frac{1}{2}} \cdot 1

= 2 (x^{4} - 4 x)^{\frac{1}{2}} x^{3} - 2 (x^{4} - 4 x)^{\frac{1}{2}} \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= 2 (x^{4} - 4 x)^{\frac{1}{2}} x^{3} - 2 (x^{4} - 4 x)^{\frac{1}{2}}

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(y + \frac{2}{5}) (12 y^{2} - 12 y^{3})

(3 x^{\frac{1}{2}} + 5) (3 x^{\frac{1}{2}} - 5)

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What is expand (x^4-4x)^{1/2}*2(x^3-1) ?
The solution to expand (x^4-4x)^{1/2}*2(x^3-1) is 2(x^4-4x)^{1/2}x^3-2(x^4-4x)^{1/2}