What is expand (3(x-1)^2)/2 ?

The solution to expand (3(x-1)^2)/2 is (3x^2)/2-3x+3/2

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expand (3(x-1)^2)/2

expand

\frac{3 ( x - 1 ) ^{2}}{2}

\frac{3 x ^{2}}{2} - 3 x + \frac{3}{2}

Solution steps

\frac{3 ( x - 1 ) ^{2}}{2}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{3 ( x ^{2} - 2 x + 1 )}{2}

Expand

3 (x^{2} - 2 x + 1) : 3 x^{2} - 6 x + 3

= \frac{3 x ^{2} - 6 x + 3}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} - 6 x + 3}{2} = \frac{3 x ^{2}}{2} - \frac{6 x}{2} + \frac{3}{2}

= \frac{3 x ^{2}}{2} - \frac{6 x}{2} + \frac{3}{2}

Divide the numbers:

\frac{6}{2} = 3

= \frac{3 x ^{2}}{2} - 3 x + \frac{3}{2}

\frac{( 1 - a ) ^{2}}{a ^{2} + 2 a + 1}

cos (x) sin (x) (1 + cos (x))

(5 e - 5 t sin (2 π t) + 2 π (1 - e - 5 t) cos (2 π t))^{2}

x^{2 (2 n + 2)}

e^{4 (1 + 2 t)}

What is expand (3(x-1)^2)/2 ?
The solution to expand (3(x-1)^2)/2 is (3x^2)/2-3x+3/2