What is expand (f\circ g)(2x+3)(x^2-1) ?

The solution to expand (f\circ g)(2x+3)(x^2-1) is 2\circ fgx^3+3\circ fgx^2-2\circ fgx-3\circ fg

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expand (f\circ g)(2x+3)(x^2-1)

expand

(f \circ g) (2 x + 3) (x^{2} - 1)

2 \circ f g x^{3} + 3 \circ f g x^{2} - 2 \circ f gx - 3 \circ f g

Solution steps

(f \circ g) (2 x + 3) (x^{2} - 1)

= (\circ f g) (2 x + 3) (x^{2} - 1)

Expand

(2 x + 3) (x^{2} - 1) : 2 x^{3} + 3 x^{2} - 2 x - 3

= (f \circ g) (2 x^{3} + 3 x^{2} - 2 x - 3)

Expand

(f \circ g) (2 x^{3} + 3 x^{2} - 2 x - 3) : 2 \circ f g x^{3} + 3 \circ f g x^{2} - 2 \circ f gx - 3 \circ f g

= 2 \circ f g x^{3} + 3 \circ f g x^{2} - 2 \circ f gx - 3 \circ f g

(sin^{2} (x^{2} - 4) \cdot cos (x + 2)) \cdot (x - 2)

\frac{5 x ^{2} + 6 x + 9}{( x - 3 ) ^{2} ( x + 1 ) ^{2}}

\frac{d ^{2}}{d x ^{2}} ((y) ((4 x^{2} - 1)^{2}))

(cot (x) - tan (x)) sin^{2} (x)

4 π (\frac{125 - 21 21}{3} - 221)

What is expand (f\circ g)(2x+3)(x^2-1) ?
The solution to expand (f\circ g)(2x+3)(x^2-1) is 2\circ fgx^3+3\circ fgx^2-2\circ fgx-3\circ fg