What is expand (3x^2+4x+2)/(2(y-1)) ?

The solution to expand (3x^2+4x+2)/(2(y-1)) is (3x^2+4x+2)/(2y-2)

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expand (3x^2+4x+2)/(2(y-1))

expand

\frac{3 x ^{2} + 4 x + 2}{2 ( y - 1 )}

\frac{3 x ^{2} + 4 x + 2}{2 y - 2}

Solution steps

\frac{3 x ^{2} + 4 x + 2}{2 ( y - 1 )}

Expand

2 (y - 1) : 2 y - 2

= \frac{3 x ^{2} + 4 x + 2}{2 y - 2}

\frac{e ^{- 2 s} ( t + 2 ) + 3}{( s + 2 ) ( s + 5 )}

(csc (x) + 1) (sec (x) - tan (x))

(x - \frac{1}{3}) (x + 6)

15 (1 + lo g_{2} (5))

2 (\frac{2 ( x - 3 ) ^{\frac{5}{2}}}{5} + 2 (x - 3)^{\frac{3}{2}}) + C

What is expand (3x^2+4x+2)/(2(y-1)) ?
The solution to expand (3x^2+4x+2)/(2(y-1)) is (3x^2+4x+2)/(2y-2)