What is (x+3/2)(x^2+3x+y^2) ?

The solution to (x+3/2)(x^2+3x+y^2) is ((2x+3)(x^2+3x+y^2))/2

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simplify (x+3/2)(x^2+3x+y^2)

simplify

(x + \frac{3}{2}) (x^{2} + 3 x + y^{2})

\frac{( 2 x + 3 ) ( x ^{2} + 3 x + y ^{2} )}{2}

Solution steps

(x + \frac{3}{2}) (x^{2} + 3 x + y^{2})

Simplify

x + \frac{3}{2} : \frac{2 x + 3}{2}

= \frac{2 x + 3}{2} (x^{2} + 3 x + y^{2})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 x + 3 ) ( x ^{2} + 3 x + y ^{2} )}{2}

(5 - 11) (7 + 23)

3 x^{2} y d x - (3 x^{3} - y^{3}) d y

(1 - cos (x)) (1 + sec (x) cot (x) = sin (x))

x^{\frac{1}{2}} (x - 1)

(x - \frac{11}{2}) (x - \frac{5}{2})

What is (x+3/2)(x^2+3x+y^2) ?
The solution to (x+3/2)(x^2+3x+y^2) is ((2x+3)(x^2+3x+y^2))/2