What are the solutions to the equation 0=x^2-1 ?

The solutions to the equation 0=x^2-1 are x=1,x=-1

Find the zeros of 0=x^2-1

The zeros of 0=x^2-1 are x=1,x=-1

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0 = x^{2} - 1

x = 1, x = - 1

Solution steps

0 = x^{2} - 1

Switch sides

x^{2} - 1 = 0

Move

1

to the right side

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

(\frac{2 x y ^{4}}{z})^{3}

\frac{4 a ^{2} - 3 a}{a}

5 \leq \frac{- w + 6}{2}

- \frac{x}{12} + 13 < 15

\frac{9}{8} \times \frac{7}{8}

What are the solutions to the equation 0=x^2-1 ?
The solutions to the equation 0=x^2-1 are x=1,x=-1
Find the zeros of 0=x^2-1
The zeros of 0=x^2-1 are x=1,x=-1