What is expand 1/((x^2+2)(x^2+3)) ?

The solution to expand 1/((x^2+2)(x^2+3)) is 1/(x^4+5x^2+6)

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expand 1/((x^2+2)(x^2+3))

expand

\frac{1}{( x ^{2} + 2 ) ( x ^{2} + 3 )}

\frac{1}{x ^{4} + 5 x ^{2} + 6}

Solution steps

\frac{1}{( x ^{2} + 2 ) ( x ^{2} + 3 )}

Expand

(x^{2} + 2) (x^{2} + 3) : x^{4} + 5 x^{2} + 6

= \frac{1}{x ^{4} + 5 x ^{2} + 6}

\frac{- 4 - 3 s}{( x + 1 ) ^{2}}

(cos (x) cos (y) - cot (x)) d x - (sin (x) sin (y)) d y

8 (ln (x) + 1)

\frac{5 x}{e ^{x} ( 1 + x )}

84 (12 x - 14 y = 20)

What is expand 1/((x^2+2)(x^2+3)) ?
The solution to expand 1/((x^2+2)(x^2+3)) is 1/(x^4+5x^2+6)