What is expand log_{5}(\sqrt[3]{x^2+6}) ?

The solution to expand log_{5}(\sqrt[3]{x^2+6}) is 1/3 log_{5}(x^2+6)

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expand log_{5}(\sqrt[3]{x^2+6})

expand

\frac{1}{3} lo g_{5} (x^{2} + 6)

Solution steps

Rewrite as

= lo g_{5} ((x^{2} + 6)^{\frac{1}{3}})

Apply log rule

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x),

assuming

x \geq 0

= \frac{1}{3} lo g_{5} (x^{2} + 6)

(x + 10 y = 50,) (x + 5 y = 44)

\frac{3 ^{x + 2}}{3 ^{x + 1}}

(x + \frac{3}{5}) (x - \frac{3}{5})

(1 - 2 - x) \cdot (1 + 2 - x)

((x + 1)^{2} + y^{2} + (x - 1)^{2} + y^{2})^{2}

What is expand log_{5}(\sqrt[3]{x^2+6}) ?
The solution to expand log_{5}(\sqrt[3]{x^2+6}) is 1/3 log_{5}(x^2+6)