What is expand (1+sin(θ))^2sec^2(θ) ?

The solution to expand (1+sin(θ))^2sec^2(θ) is sec^2(θ)+2sec^2(θ)sin(θ)+sec^2(θ)sin^2(θ)

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expand (1+sin(θ))^2sec^2(θ)

expand

(1 + sin (θ))^{2} sec^{2} (θ)

sec^{2} (θ) + 2 sec^{2} (θ) sin (θ) + sec^{2} (θ) sin^{2} (θ)

Solution steps

(1 + sin (θ))^{2} sec^{2} (θ)

= sec^{2} (θ) (1 + sin (θ))^{2}

Expand

(1 + sin (θ))^{2} : 1 + 2 sin (θ) + sin^{2} (θ)

= sec^{2} (θ) (1 + 2 sin (θ) + sin^{2} (θ))

Apply the distributive law:

m (a + b + c) = ma + mb + m c

sec^{2} (θ) (1 + 2 sin (θ) + sin^{2} (θ)) = sec^{2} (θ) \cdot 1 + sec^{2} (θ) \cdot 2 sin (θ) + sec^{2} (θ) sin^{2} (θ)

= sec^{2} (θ) \cdot 1 + sec^{2} (θ) \cdot 2 sin (θ) + sec^{2} (θ) sin^{2} (θ)

Simplify

sec^{2} (θ) \cdot 1 + sec^{2} (θ) \cdot 2 sin (θ) + sec^{2} (θ) sin^{2} (θ) : sec^{2} (θ) + 2 sec^{2} (θ) sin (θ) + sec^{2} (θ) sin^{2} (θ)

= sec^{2} (θ) + 2 sec^{2} (θ) sin (θ) + sec^{2} (θ) sin^{2} (θ)

(csc (θ) + sec (θ))^{2}

(n + 1)^{2} (\frac{2}{3})^{n}

9 z^{2} (4 e + 7 f) + 4 e + 7 f

(5 a + b^{5}) l e f t (5 a - b^{5})

\frac{( 2 x + 3 ) ^{3}}{x ^{2} + 4}

What is expand (1+sin(θ))^2sec^2(θ) ?
The solution to expand (1+sin(θ))^2sec^2(θ) is sec^2(θ)+2sec^2(θ)sin(θ)+sec^2(θ)sin^2(θ)