What is expand ((2x+3)(x-4))/8 ?

The solution to expand ((2x+3)(x-4))/8 is (x^2)/4-(5x)/8-3/2

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expand ((2x+3)(x-4))/8

expand

\frac{( 2 x + 3 ) ( x - 4 )}{8}

\frac{x ^{2}}{4} - \frac{5 x}{8} - \frac{3}{2}

Solution steps

\frac{( 2 x + 3 ) ( x - 4 )}{8}

Expand

(2 x + 3) (x - 4) : 2 x^{2} - 5 x - 12

= \frac{2 x ^{2} - 5 x - 12}{8}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} - 5 x - 12}{8} = \frac{2 x ^{2}}{8} - \frac{5 x}{8} - \frac{12}{8}

= \frac{2 x ^{2}}{8} - \frac{5 x}{8} - \frac{12}{8}

Cancel

\frac{2 x ^{2}}{8} : \frac{x ^{2}}{4}

= \frac{x ^{2}}{4} - \frac{5 x}{8} - \frac{12}{8}

Cancel

\frac{12}{8} : \frac{3}{2}

= \frac{x ^{2}}{4} - \frac{5 x}{8} - \frac{3}{2}

\frac{x + 2}{( x - 2 ) ( x + 1 )}

\frac{9 ( - t ^{2} + 9 )}{( t ^{2} + 9 ) ^{2}}

- 4 (e + 6)

- 2 (6 ln (2) - 2)

(2 x - \frac{1}{x ^{2}})^{9}

What is expand ((2x+3)(x-4))/8 ?
The solution to expand ((2x+3)(x-4))/8 is (x^2)/4-(5x)/8-3/2