What is expand-(s+3)/(s(s-3)(s-2)) ?

The solution to expand-(s+3)/(s(s-3)(s-2)) is -(s+3)/(s^3-5s^2+6s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(s+3)/(s(s-3)(s-2))

expand

- \frac{s + 3}{s ( s - 3 ) ( s - 2 )}

- \frac{s + 3}{s ^{3} - 5 s ^{2} + 6 s}

Solution steps

- \frac{s + 3}{s ( s - 3 ) ( s - 2 )}

Expand

s (s - 3) (s - 2) : s^{3} - 5 s^{2} + 6 s

= - \frac{s + 3}{s ^{3} - 5 s ^{2} + 6 s}

(cos^{2} (x) + y sin (2 x)) y^{'} (x) + y^{2}

(4 - (x + 15)) (- 4 + x + 15)

\frac{sin ( x ) + cot ( x ) ( 1 + cos ( x ) )}{1 + cos ( x )}

\frac{( 3 y - 5 ) ^{2}}{2}

lo g_{4} (64)

What is expand-(s+3)/(s(s-3)(s-2)) ?
The solution to expand-(s+3)/(s(s-3)(s-2)) is -(s+3)/(s^3-5s^2+6s)