What is expand (e^x+4)(7e^x-9) ?

The solution to expand (e^x+4)(7e^x-9) is 7e^{2x}+19e^x-36

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expand (e^x+4)(7e^x-9)

expand

(e^{x} + 4) (7 e^{x} - 9)

7 e^{2 x} + 19 e^{x} - 36

Solution steps

(e^{x} + 4) (7 e^{x} - 9)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = e^{x}, b = 4, c = 7 e^{x}, d = - 9

= e^{x} \cdot 7 e^{x} + e^{x} (- 9) + 4 \cdot 7 e^{x} + 4 (- 9)

Apply minus-plus rules

+ (- a) = - a

= 7 e^{x} e^{x} - 9 e^{x} + 4 \cdot 7 e^{x} - 4 \cdot 9

Simplify

7 e^{x} e^{x} - 9 e^{x} + 4 \cdot 7 e^{x} - 4 \cdot 9 : 7 e^{2 x} + 19 e^{x} - 36

= 7 e^{2 x} + 19 e^{x} - 36

s (t - π)

\frac{a ^{2} - b}{2 ( a - b )}

(4 - 2 x - 4) (4 - 2 x + 4)

(\frac{u}{v} - w) (\frac{u}{v} + w)

\frac{2}{s ( 4 s ^{2} + 3 s + 1 )}

What is expand (e^x+4)(7e^x-9) ?
The solution to expand (e^x+4)(7e^x-9) is 7e^{2x}+19e^x-36